python将列表变字典的两种要领:
1、要领:再组织一个列表list2 = [‘1’,‘2’,‘3’],运用zip转换为元组后,在将元组转换为字典。
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list1 = ['key1','key2','key3'] list2 = ['1','2','3'] dict(zip(list1,list2)) {'key1':'1','key2':'2','key3':'3'}
2、将嵌套列表转为字典,有两种要领,
new_list= [['key1','value1'],['key2','value2'],['key3','value3']] dict(list) {'key3': 'value3', 'key2': 'value2', 'key1': 'value1'}
或许如许:
new_list= [['key1','value1'],['key2','value2'],['key3','value3']] new_dict = {} for i in new_list: new_dict[i[0]] = i[1] #字典赋值,左侧为key,右侧为value new_dict {'key3': 'value3', 'key2': 'value2', 'key1': 'value1'}
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