在 Python 里怎样手工举行耽误【Python教程】,python

我想知道如安在Python剧本中加时候耽误。

import time
time.sleep(5)   # Delays for 5 seconds. You can also use a float value.

这是另一个例子，约莫每分钟运转一次：

import timewhile True:
    print("This prints once a minute.")
    time.sleep(60) # Delay for 1 minute (60 seconds).

您能够sleep()在时候模块中运用该功用。它能够采纳浮动参数举行亚秒级分辨率。

from time import sleep
sleep(0.1) # Time in seconds.

在 Python 里怎样手工举行耽误？

在一个线程中我发起就寝功用：

>>> from time import sleep
>>> sleep(4)

这实际上停息了操作系统调用它的线程的处置惩罚，许可其他线程和历程在休眠时实行。

将其用于此目标，或仅仅是为了耽误实行某个功用。比方：

>>> def party_time():
...     print('hooray!')
... 
>>> sleep(3); party_time()
hooray!

打了3秒后打印出来Enter。

运用sleep多个线程和历程的示例

再次，sleep停息你的线程 – 它运用零处置惩罚才能。

为了演示，建立一个如许的剧本（我首先在交互式Python 3.5 shell中尝试过这个，但子历程party_later由于某种原因找不到该函数）：

from concurrent.futures import ThreadPoolExecutor, ProcessPoolExecutor, as_completed
from time import sleep, time
def party_later(kind='', n=''):
    sleep(3)
    return kind + n + ' party time!: ' + __name__
def main():
    with ProcessPoolExecutor() as proc_executor:
        with ThreadPoolExecutor() as thread_executor:
            start_time = time()
            proc_future1 = proc_executor.submit(party_later, kind='proc', n='1')
            proc_future2 = proc_executor.submit(party_later, kind='proc', n='2')
            thread_future1 = thread_executor.submit(party_later, kind='thread', n='1')
            thread_future2 = thread_executor.submit(party_later, kind='thread', n='2')
            for f in as_completed([
              proc_future1, proc_future2, thread_future1, thread_future2,]):
                print(f.result())
            end_time = time()
    print('total time to execute four 3-sec functions:', end_time - start_time)
if __name__ == '__main__':
    main()

此剧本的示例输出：

thread1 party time!: __main__
thread2 party time!: __main__
proc1 party time!: __mp_main__
proc2 party time!: __mp_main__
total time to execute four 3-sec functions: 3.4519670009613037

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