我们需要对类根据类中的某一个属性(或许多个属性)来对类的对象举行排序,有两种要领能够完成,一种要领是类完成Comparable<T>
接口,然后挪用Collections.sort(List)
要领举行排序,另一种要领是类不完成Comparable<T>
接口,而在排序时运用Collections.sort(List, Comparator<T>)
要领,并完成个中的Comparator<T>接口。
免费进修视频教程引荐:java视频教程
先建立一个简朴的门生类:
public class Student { private String name; private int age; public Student() {} public Student(String name, int age) { this.name = name; this.age = age; } public String getName() { return name; } public void setName(String name) { this.name = name; } public int getAge() { return age; } public void setAge(int age) { this.age = age; } }
1、经由过程类完成Comparable<T>接口举行排序
public class Student implements Comparable<Student>{ private String name; private int age; public Student() {} public Student(String name, int age) { this.name = name; this.age = age; } public String getName() { return name; } public void setName(String name) { this.name = name; } public int getAge() { return age; } public void setAge(int age) { this.age = age; } /** * 将对象按姓名字典序升序排序 * @param o * @return */ @Override public int compareTo(Student o) { return this.name.compareTo(o.getName()); } @Override public String toString() { return "Student{" + "name='" + name + '\'' + ", age=" + age + '}'; } }
2、经由过程在Collections.sort()要领中完成Comparable<T>接口来完成排序
public class Client { public static void main(String[] args){ List<Student> students = new ArrayList<>(); students.add(new Student("a", 18)); students.add(new Student("c", 19)); students.add(new Student("b", 20)); Collections.sort(students, new Comparator<Student>() { @Override public int compare(Student o1, Student o2) { return o1.getAge()>o2.getAge()? -1:(o1.getAge()==o2.getAge()? 0:1); } }); for(Student student:students){ System.out.println(student.toString()); } } }
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