媒介:在MySQL中 CONCAT ()函数用于将多个字符串衔接成一个字符串,应用此函数我们能够将本来一步没法获得的sql拼接出来,在工作中或许会轻易许多,下面重要引见下几个经常运用的场景。
注:适用于5.7版本 低版本能够稍许差别。
1.拼接查询一切用户
SELECT DISTINCT CONCAT( 'User: \'', USER, '\'@\'', HOST, '\';' ) AS QUERY FROM mysql.USER; # 当拼接字符串中涌现'时 需运用\转义符
2.拼接DROP table
SELECT CONCAT( 'DROP table ', TABLE_NAME, ';' ) FROM information_schema. TABLES WHERE TABLE_SCHEMA = 'test';
3.拼接kill衔接
SELECT concat('KILL ', id, ';') FROM information_schema. PROCESSLIST WHERE STATE LIKE 'Creating sort index';
4.拼接建立数据库语句
SELECT CONCAT( 'create database ', '`', SCHEMA_NAME, '`', ' DEFAULT CHARACTER SET ', DEFAULT_CHARACTER_SET_NAME, ';' ) AS CreateDatabaseQuery FROM information_schema.SCHEMATA WHERE SCHEMA_NAME NOT IN ( 'information_schema', 'performance_schema', 'mysql', 'sys' );
5.拼接建立用户的语句
SELECT CONCAT( 'create user \'', user, '\'@\'', Host, '\'' ' IDENTIFIED BY PASSWORD \'', authentication_string, '\';' ) AS CreateUserQuery FROM mysql.`user` WHERE `User` NOT IN ( 'root', 'mysql.session', 'mysql.sys' ); #有暗码字符串哦 在其他实例实行 可直接建立出与本实例雷同暗码的用户
6.导出权限剧本 这个shell剧本也用到了拼接
#!/bin/bash #Function export user privileges pwd=yourpass expgrants() { mysql -B -u'root' -p${pwd} -N $@ -e "SELECT CONCAT( 'SHOW GRANTS FOR ''', user, '''@''', host, ''';' ) AS query FROM mysql.user" | \ mysql -u'root' -p${pwd} $@ | \ sed 's/\(GRANT .*\)/\1;/;s/^\(Grants for .*\)/-- \1 /;/--/{x;p;x;}' } expgrants > /tmp/grants.sql echo "flush privileges;" >> /tmp/grants.sql
7.查找表碎片
SELECT t.TABLE_SCHEMA, t.TABLE_NAME, t.TABLE_ROWS, concat(round(t.DATA_LENGTH / 1024 / 1024, 2), 'M') AS size, t.INDEX_LENGTH, concat(round(t.DATA_FREE / 1024 / 1024, 2), 'M') AS datafree FROM information_schema.tables t WHERE t.TABLE_SCHEMA = 'test' order by DATA_LENGTH desc;
8.查找无主键表 这个没用到拼接 也分享出来吧
#查找某一个库无主键表 SELECT table_schema, table_name FROM information_schema.TABLES WHERE table_schema = 'test' AND TABLE_NAME NOT IN ( SELECT table_name FROM information_schema.table_constraints t JOIN information_schema.key_column_usage k USING ( constraint_name, table_schema, table_name ) WHERE t.constraint_type = 'PRIMARY KEY' AND t.table_schema = 'test' ); #查找除体系库外 无主键表 SELECT t1.table_schema, t1.table_name FROM information_schema. TABLES t1 LEFT OUTER JOIN information_schema.TABLE_CONSTRAINTS t2 ON t1.table_schema = t2.TABLE_SCHEMA AND t1.table_name = t2.TABLE_NAME AND t2.CONSTRAINT_NAME IN ('PRIMARY') WHERE t2.table_name IS NULL AND t1.TABLE_SCHEMA NOT IN ( 'information_schema', 'performance_schema', 'mysql', 'sys' ) ;
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